Every integer greater than 1 is either prime or can be represented as the unique product of powers of prime numbers.
Proof:
(1) First, prove existence. It is true for the base case where n=2 since 2 is a prime.
(2) Assume that it is true for all i with i \le n
(3) For n+1, if n+1 is prime, then it is true. If n+1 is not prime, then there exists integers a,b such that n+1 = ab with a \le n and b \le n. Since a \le n and b \le n, they can be represented by a prime or a product of primes with a=p_1p_2\dots{p_n} and b=q_1q_2\dots{q_n}
(4) Then n+1 = ab = p_1p_2\dots{p_n}q_1q_2\dots{q_n} which means that n+1 can be represented as a product of powers of prime numbers.
(5) Assume that there is an integer that has two different product of powers of prime numbers.
(6) Let y be the least integer where this is true so that y = p_1p_2\dots{p_m} = q_1q_2\dots{q_n} with p_1\dots{p_m} and q_1\dots{q_n}.
(7) From Euclid's Generalized Lemma, p_1 divides q_i where 1 \le i \le n. But, then \frac{y}{p_1} = p_2\dots{p_m} = \frac{q_1q_2\dots{q_n}}{p_1} which is smaller than n and contradicts our assumption in step(6).
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